package com.sheng.leetcode.year2022.month09.day14;

import org.junit.Test;

import java.util.Arrays;

/**
 * @author liusheng
 * @date 2022/09/14
 *<p>
 * 1619. 删除某些元素后的数组均值<p>
 *<p>
 * 给你一个整数数组arr，请你删除最小5%的数字和最大 5%的数字后，剩余数字的平均值。<p>
 * 与 标准答案误差在10^-5的结果都被视为正确结果。<p>
 *<p>
 * 示例 1：<p>
 * 输入：arr = [1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3]<p>
 * 输出：2.00000<p>
 * 解释：删除数组中最大和最小的元素后，所有元素都等于 2，所以平均值为 2 。<p>
 *<p>
 * 示例 2：<p>
 * 输入：arr = [6,2,7,5,1,2,0,3,10,2,5,0,5,5,0,8,7,6,8,0]<p>
 * 输出：4.00000<p>
 *<p>
 * 示例 3：<p>
 * 输入：arr = [6,0,7,0,7,5,7,8,3,4,0,7,8,1,6,8,1,1,2,4,8,1,9,5,4,3,8,5,10,8,6,6,1,0,6,10,8,2,3,4]<p>
 * 输出：4.77778<p>
 *<p>
 * 示例 4：<p>
 * 输入：arr = [9,7,8,7,7,8,4,4,6,8,8,7,6,8,8,9,2,6,0,0,1,10,8,6,3,3,5,1,10,9,0,7,10,0,10,4,1,10,6,9,3,6,0,0,2,7,0,6,7,2,9,7,7,3,0,1,6,1,10,3]<p>
 * 输出：5.27778<p>
 *<p>
 * 示例 5：<p>
 * 输入：arr = [4,8,4,10,0,7,1,3,7,8,8,3,4,1,6,2,1,1,8,0,9,8,0,3,9,10,3,10,1,10,7,3,2,1,4,9,10,7,6,4,0,8,5,1,2,1,6,2,5,0,7,10,9,10,3,7,10,5,8,5,7,6,7,6,10,9,5,10,5,5,7,2,10,7,7,8,2,0,1,1]<p>
 * 输出：5.29167<p>
 *<p>
 * 提示：<p>
 *<p>
 * 20 <= arr.length <= 1000<p>
 * arr.length是20的倍数<p>
 * 0 <= arr[i] <= 105<p>
 *<p>
 * 来源：力扣（LeetCode）<p>
 * 链接：<a href="https://leetcode.cn/problems/mean-of-array-after-removing-some-elements">...</a><p>
 * 著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。<p>
 */
public class LeetCode1619 {

    @Test
    public void test01() {
//        int[] arr = {1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3};
//        int[] arr = {6,2,7,5,1,2,0,3,10,2,5,0,5,5,0,8,7,6,8,0};
//        int[] arr = {6,0,7,0,7,5,7,8,3,4,0,7,8,1,6,8,1,1,2,4,8,1,9,5,4,3,8,5,10,8,6,6,1,0,6,10,8,2,3,4};
//        int[] arr = {9,7,8,7,7,8,4,4,6,8,8,7,6,8,8,9,2,6,0,0,1,10,8,6,3,3,5,1,10,9,0,7,10,0,10,4,1,10,6,9,3,6,0,0,2,7,0,6,7,2,9,7,7,3,0,1,6,1,10,3};
        int[] arr = {4,8,4,10,0,7,1,3,7,8,8,3,4,1,6,2,1,1,8,0,9,8,0,3,9,10,3,10,1,10,7,3,2,1,4,9,10,7,6,4,0,8,5,1,2,1,6,2,5,0,7,10,9,10,3,7,10,5,8,5,7,6,7,6,10,9,5,10,5,5,7,2,10,7,7,8,2,0,1,1};
        System.out.println(new Solution().trimMean(arr));
    }
}
class Solution {
    public double trimMean(int[] arr) {
        Arrays.sort(arr);
        int[] ints = Arrays.copyOfRange(arr, (int) (arr.length * 0.05), (int) (arr.length * 0.95));
        return Arrays.stream(ints).average().getAsDouble();
    }
}
